Can You Outwit Tens of Thousands of New York Times Readers?

Illustration for article titled Can You Outwit Tens of Thousands of iNew York Times/i Readers?

Here’s a fantastic exercise in thinking about thinking: The Upshot at the NYT is hosting an interactive puzzle that pits you against every other person who attempts the puzzle. It’s... a bit of a mind game.

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It’s a digitized twist on a classic problem from economics:

We are asking them – and you – to pick a number from 0 to 100, with that number representing your best guess of two-thirds of the average of all numbers chosen in the contest.

For example, if the average of all numbers is 62, you would win by picking 41. (No decimals or fractions in your numbers are allowed.) If the average is 39, you’d win by picking 26. If the average is 31, you’d win by picking 21.

Stop and think for a second. What is everyone else going to do?

Take a crack at it over at the NYT, then head back here to discuss your result—especially if you enjoy io9’s Sunday Puzzle series. I’m curious to hear whether people who solve brain teasers recreationally approach the NYT’s challenge differently than others.

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Contact the author at rtgonzalez@io9.com.

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DISCUSSION

volante3192
Volante3192

So if the number you pick has to be 2/3rds of the average of all picked numbers, then the highest number picked should be 67.

But then if everyone picks 67, then the obvious choice would be 45. But with 45 the obvious choice, it’s now 30...then 20...then 13, 9, 6, 4, 3, 2 before finally landing on 1.

Everyone should’ve picked 1.

Edit: apparently the used graphic blinded me to the fact that ‘0’ is an option. I’m sticking with my theory since normal people just wouldn’t pick 0. Plus you can have a few 0s and still have a 2/3rds average that rounds to 1.